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Chemistry

Chemistry · Quick practice · answer shown after each question

Volumetric analysis calculations

Question 1 of 10

Question 1 of 10

10 cm³ of 0.05 mol/dm³ H₂SO₄ neutralised 25.0 cm³ of NaOH. H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. Find the concentration of the NaOH.

Question 2 of 10

Question 2 of 10

25 cm³ of 0.15 mol/dm³ HCl neutralised 25.0 cm³ of NaOH solution. What is the concentration of the NaOH?

Question 3 of 10

Question 3 of 10

A primary standard should be

Question 4 of 10

Question 4 of 10

A 0.25 mol/dm³ solution of KOH has what mass concentration?

Question 5 of 10

Question 5 of 10

A 0.5 mol/dm³ solution of HCl has what mass concentration?

Question 6 of 10

Question 6 of 10

A standard solution is one

Question 7 of 10

Question 7 of 10

20 cm³ of 0.2 mol/dm³ H₂SO₄ neutralised 25.0 cm³ of NaOH. H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. Find the concentration of the NaOH.

Question 8 of 10

Question 8 of 10

Phenolphthalein is suitable for titrating

Question 9 of 10

Question 9 of 10

In 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O, the mole ratio of NaOH to H₂SO₄ is 2 : 1.

Question 10 of 10

Question 10 of 10

10.6 g of anhydrous sodium carbonate was dissolved in water and made up to 250 cm³. 25.0 cm³ of this solution required 25 cm³ of hydrochloric acid for neutralisation using methyl orange. Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂ (Na₂CO₃ = 106) Calculate (a) the concentration of Na₂CO₃ in mol/dm³, (b) the moles of Na₂CO₃ in 25.0 cm³, (c) the concentration of HCl in mol/dm³, (d) the concentration of HCl in g/dm³ (HCl = 36.5).

Questions written by OtisamLMS in the style of the WASSCE. They are not WAEC past questions.