Skip to content
OtisamLMS
Mathematics

Mathematics · Quick practice · answer shown after each question

Expansion and factorisation

Question 1 of 10

Question 1 of 10

(a) Expand and simplify 4(x + 5) − (x − 3). (b) Factorise x² + 2x − 15. (c) Hence solve x² + 2x − 15 = 0.

Question 2 of 10

Question 2 of 10

(a) Expand and simplify 2(x + 3) − (x − 6). (b) Factorise x² − 3x − 18. (c) Hence solve x² − 3x − 18 = 0.

Question 3 of 10

Question 3 of 10

Factorising is the reverse of expanding.

Question 4 of 10

Question 4 of 10

When (x + 6)(x + 3) is expanded, the constant term is ___.

Question 5 of 10

Question 5 of 10

(a) Expand and simplify 4(x + 1) − (x − 5). (b) Factorise x² − 4x − 5. (c) Hence solve x² − 4x − 5 = 0.

Question 6 of 10

Question 6 of 10

Expand (x + 6)(x − 3).

Question 7 of 10

Question 7 of 10

(x + 1)² = x² + 1.

Question 8 of 10

Question 8 of 10

(x + 5)² expands to

Question 9 of 10

Question 9 of 10

When (x + 6)(x + 4) is expanded, the constant term is ___.

Question 10 of 10

Question 10 of 10

Factorise 2xy + 6x.

Questions written by OtisamLMS in the style of the BECE. They are not WAEC past questions.